Integrand size = 21, antiderivative size = 95 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=-\frac {b d n (f x)^{1+m}}{f (1+m)^2}-\frac {b e n (f x)^{2+m}}{f^2 (2+m)^2}+\frac {d (f x)^{1+m} \left (a+b \log \left (c x^n\right )\right )}{f (1+m)}+\frac {e (f x)^{2+m} \left (a+b \log \left (c x^n\right )\right )}{f^2 (2+m)} \]
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Time = 0.06 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {45, 2392} \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\frac {d (f x)^{m+1} \left (a+b \log \left (c x^n\right )\right )}{f (m+1)}+\frac {e (f x)^{m+2} \left (a+b \log \left (c x^n\right )\right )}{f^2 (m+2)}-\frac {b d n (f x)^{m+1}}{f (m+1)^2}-\frac {b e n (f x)^{m+2}}{f^2 (m+2)^2} \]
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Rule 45
Rule 2392
Rubi steps \begin{align*} \text {integral}& = \frac {d (f x)^{1+m} \left (a+b \log \left (c x^n\right )\right )}{f (1+m)}+\frac {e (f x)^{2+m} \left (a+b \log \left (c x^n\right )\right )}{f^2 (2+m)}-(b n) \int (f x)^m \left (\frac {d}{1+m}+\frac {e x}{2+m}\right ) \, dx \\ & = \frac {d (f x)^{1+m} \left (a+b \log \left (c x^n\right )\right )}{f (1+m)}+\frac {e (f x)^{2+m} \left (a+b \log \left (c x^n\right )\right )}{f^2 (2+m)}-(b n) \int \left (\frac {d (f x)^m}{1+m}+\frac {e (f x)^{1+m}}{f (2+m)}\right ) \, dx \\ & = -\frac {b d n (f x)^{1+m}}{f (1+m)^2}-\frac {b e n (f x)^{2+m}}{f^2 (2+m)^2}+\frac {d (f x)^{1+m} \left (a+b \log \left (c x^n\right )\right )}{f (1+m)}+\frac {e (f x)^{2+m} \left (a+b \log \left (c x^n\right )\right )}{f^2 (2+m)} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.67 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=x (f x)^m \left (-\frac {b d n}{(1+m)^2}-\frac {b e n x}{(2+m)^2}+\frac {d \left (a+b \log \left (c x^n\right )\right )}{1+m}+\frac {e x \left (a+b \log \left (c x^n\right )\right )}{2+m}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(352\) vs. \(2(95)=190\).
Time = 0.22 (sec) , antiderivative size = 353, normalized size of antiderivative = 3.72
method | result | size |
parallelrisch | \(-\frac {-2 x^{2} \left (f x \right )^{m} a e -4 x \left (f x \right )^{m} a d -x^{2} \left (f x \right )^{m} a e \,m^{3}-4 x^{2} \left (f x \right )^{m} a e \,m^{2}-x \left (f x \right )^{m} a d \,m^{3}-5 x^{2} \left (f x \right )^{m} a e m +x^{2} \left (f x \right )^{m} b e n -5 x \left (f x \right )^{m} a d \,m^{2}-8 x \left (f x \right )^{m} a d m +4 x \left (f x \right )^{m} b d n -4 x \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b d -2 x^{2} \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b e -x^{2} \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b e \,m^{3}-4 x^{2} \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b e \,m^{2}+x^{2} \left (f x \right )^{m} b e \,m^{2} n -x \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b d \,m^{3}-5 x^{2} \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b e m +2 x^{2} \left (f x \right )^{m} b e m n -5 x \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b d \,m^{2}+x \left (f x \right )^{m} b d \,m^{2} n -8 x \left (f x \right )^{m} \ln \left (c \,x^{n}\right ) b d m +4 x \left (f x \right )^{m} b d m n}{\left (m^{2}+4 m +4\right ) \left (m^{2}+2 m +1\right )}\) | \(353\) |
risch | \(\text {Expression too large to display}\) | \(1056\) |
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Leaf count of result is larger than twice the leaf count of optimal. 235 vs. \(2 (95) = 190\).
Time = 0.33 (sec) , antiderivative size = 235, normalized size of antiderivative = 2.47 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\frac {{\left ({\left (a e m^{3} + 4 \, a e m^{2} + 5 \, a e m + 2 \, a e - {\left (b e m^{2} + 2 \, b e m + b e\right )} n\right )} x^{2} + {\left (a d m^{3} + 5 \, a d m^{2} + 8 \, a d m + 4 \, a d - {\left (b d m^{2} + 4 \, b d m + 4 \, b d\right )} n\right )} x + {\left ({\left (b e m^{3} + 4 \, b e m^{2} + 5 \, b e m + 2 \, b e\right )} x^{2} + {\left (b d m^{3} + 5 \, b d m^{2} + 8 \, b d m + 4 \, b d\right )} x\right )} \log \left (c\right ) + {\left ({\left (b e m^{3} + 4 \, b e m^{2} + 5 \, b e m + 2 \, b e\right )} n x^{2} + {\left (b d m^{3} + 5 \, b d m^{2} + 8 \, b d m + 4 \, b d\right )} n x\right )} \log \left (x\right )\right )} e^{\left (m \log \left (f\right ) + m \log \left (x\right )\right )}}{m^{4} + 6 \, m^{3} + 13 \, m^{2} + 12 \, m + 4} \]
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Leaf count of result is larger than twice the leaf count of optimal. 899 vs. \(2 (87) = 174\).
Time = 2.39 (sec) , antiderivative size = 899, normalized size of antiderivative = 9.46 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\begin {cases} \frac {- \frac {a d}{x} + a e \log {\left (x \right )} + b d \left (- \frac {n}{x} - \frac {\log {\left (c x^{n} \right )}}{x}\right ) - b e \left (\begin {cases} - \log {\left (c \right )} \log {\left (x \right )} & \text {for}\: n = 0 \\- \frac {\log {\left (c x^{n} \right )}^{2}}{2 n} & \text {otherwise} \end {cases}\right )}{f^{2}} & \text {for}\: m = -2 \\\frac {\frac {a d \log {\left (c x^{n} \right )}}{n} + a e x + \frac {b d \log {\left (c x^{n} \right )}^{2}}{2 n} - b e n x + b e x \log {\left (c x^{n} \right )}}{f} & \text {for}\: m = -1 \\\frac {a d m^{3} x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {5 a d m^{2} x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {8 a d m x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {4 a d x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {a e m^{3} x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {4 a e m^{2} x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {5 a e m x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {2 a e x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {b d m^{3} x \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {b d m^{2} n x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {5 b d m^{2} x \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {4 b d m n x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {8 b d m x \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {4 b d n x \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {4 b d x \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {b e m^{3} x^{2} \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {b e m^{2} n x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {4 b e m^{2} x^{2} \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {2 b e m n x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {5 b e m x^{2} \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} - \frac {b e n x^{2} \left (f x\right )^{m}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} + \frac {2 b e x^{2} \left (f x\right )^{m} \log {\left (c x^{n} \right )}}{m^{4} + 6 m^{3} + 13 m^{2} + 12 m + 4} & \text {otherwise} \end {cases} \]
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Time = 0.24 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.25 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\frac {b e f^{m} x^{2} x^{m} \log \left (c x^{n}\right )}{m + 2} + \frac {a e f^{m} x^{2} x^{m}}{m + 2} - \frac {b e f^{m} n x^{2} x^{m}}{{\left (m + 2\right )}^{2}} - \frac {b d f^{m} n x x^{m}}{{\left (m + 1\right )}^{2}} + \frac {\left (f x\right )^{m + 1} b d \log \left (c x^{n}\right )}{f {\left (m + 1\right )}} + \frac {\left (f x\right )^{m + 1} a d}{f {\left (m + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 212 vs. \(2 (95) = 190\).
Time = 0.33 (sec) , antiderivative size = 212, normalized size of antiderivative = 2.23 \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\frac {b e f^{m} m n x^{2} x^{m} \log \left (x\right )}{m^{2} + 4 \, m + 4} + \frac {b d f^{m} m n x x^{m} \log \left (x\right )}{m^{2} + 2 \, m + 1} + \frac {2 \, b e f^{m} n x^{2} x^{m} \log \left (x\right )}{m^{2} + 4 \, m + 4} - \frac {b e f^{m} n x^{2} x^{m}}{m^{2} + 4 \, m + 4} + \frac {b e f^{m} x^{2} x^{m} \log \left (c\right )}{m + 2} + \frac {b d f^{m} n x x^{m} \log \left (x\right )}{m^{2} + 2 \, m + 1} - \frac {b d f^{m} n x x^{m}}{m^{2} + 2 \, m + 1} + \frac {a e f^{m} x^{2} x^{m}}{m + 2} + \frac {\left (f x\right )^{m} b d x \log \left (c\right )}{m + 1} + \frac {\left (f x\right )^{m} a d x}{m + 1} \]
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Timed out. \[ \int (f x)^m (d+e x) \left (a+b \log \left (c x^n\right )\right ) \, dx=\int {\left (f\,x\right )}^m\,\left (a+b\,\ln \left (c\,x^n\right )\right )\,\left (d+e\,x\right ) \,d x \]
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